Ans: We can measure the
magnitude and direction of displacement with the help of linear
variable differential transformer (LVDT) which is
described below:-
Working
Principle:
when a sinusoidal
input Vi =VmsinѠt is applied to the primary winding, a sinusoidal flux
will link with primary winding(p), as well as two secondary windings S1 and
S2 due to high permeability of the core the reluctance of the
path will be very low . As S1, S2 are stationary and the flux is rotating, the
flux will cut both S1 and S2. So, there will be induced emf e01 and
e02 in S1 and S2 respectively. As S1 and
S2 are connected in series opposition, the differential
output, Δe0 = e01 - e02. The differential output Δe0 will
be either in phase with input voltage (Vi) or
it will be 180 out of phase with input voltage (Vi)
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Case I: core at the
midpoint between S1 and
S2
Suppose
no displacement is applied then the iron core will be in the middle of the S1 and S2 in
that case the flux linking with both S1 and
S2 will be same ideally. So, the induced emf e01 and
e02 will be equal. Hence ideally the differential
output Δe0 = e01 - e02=0. But in actual practice, there will be some differential
output due to the harmonics. This differential output is known as
residual voltage as shown in figure 2
Case II: core
moving left side
let’s us suppose a moving object is connected to the shaft and the object is moving
in the left-hand side then the flux linking
with S1 increases and that of S2 decreases. So
e01 increases and e02 decreases and the
differential output, Δe0 = e01 - e02 increases. So, there exists a linear relation
between the differential output and the displacement up to the saturation point
as shown in figure 2.and the differential output in this case is in phase
with input voltage (Vi).
Case III: Core
moving right side:
Again, let’s suppose the core is at the mid-point and a moving
object is connected to shaft and now it is moving in right hand side flux
linking with S2 increases and that of S1 decreases. So, e02 increases
and e01 decreases and the differential output, Δe0 = e02 - e01 increases again
there exists a linear relation between differential output and
the displacement up to the saturation point as shown in the figure 2 and beyond saturation point that
relation is no more linear. and the differential output in this case is
1800out of phase with
input voltage (Vi).
So, we conclude that magnitude of differential output gives the magnitude of displacement and phase angle of differential output gives the direction of displacement in this way, we can measure both direction and magnitude of the displacement by using LVDT .
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